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CS228: Probabilistic Methods in AI Winter 2008 Weekly Quiz |
| Overall Score Statistics: | ||||
|---|---|---|---|---|
| Mean | Median | Mode | Lowest | Highest |
| 84.23% | 86% | 86% (21) | 43% | 100% |
| Frequency of Scores | |
|---|---|
| Score | Number of Students |
| 100% | 19 |
| 86% | 21 |
| 71% | 11 |
| 57% | 4 |
| 43% | 2 |
| Question 1: Consider the simple Markov chain shown in the figure below. By definition, a stationary distribution | |||
|---|---|---|---|
| Type | Answer | Responses | Percent |
| Correct: | I, IV, and VI | 57 | 100% |
| Distractor: | I, III and V | 0 | 0% |
| Distractor: | II, IV, and VI | 0 | 0% |
| Distractor: | I, IV, and V | 0 | 0% |
| Distractor: | None of the above | 0 | 0% |
| Question
2: Which of the following finite state Markov chain structures cannot
have a unique statitionary distribution (under any parameterization)?
| |||
| Type | Answer | Responses | Percent |
| Correct: | Markov chain B. | 51 | 89% |
| Distractor: | Markov chain A. | 4 | 7% |
| Distractor: | Markov chain C. | 2 | 4% |
| Question 3: Suppose we are running the Gibbs sampling algorithm on the Bayesian network Answers: 1. P(x0, y1, z0) 2. P(y1 | x0, z0) 3. P(y1 | x0) 4. P(x0, z0 | y1) | |||
| Type | Answer | Responses | Percent |
| Correct: | P(y<sup>1</sup> | x<sup>0</sup>, z<sup>0</sup>) | 52 | 91% |
| Distractor: | P(x<sup>0</sup>, y<sup>1</sup>, z<sup>0</sup>) | 2 | 4% |
| Distractor: | P(y<sup>1</sup> &KPHHASH124; x<sup>0</sup>) | 2 | 4% |
| Distractor: | P(x<sup>0</sup>, z<sup>0</sup> &KPHHASH124; y<sup>1</sup>) | 1 | 2% |
| Question
4: Consider the case of exact clique tree inference applied to a DBN.
Taking the last clique in the chain to be the root, we need to perform
BOTH forward and backward message passing if we wish to solve which
inference tasks? Answers: 1. tracking (or filtering) 2. prediction 3. smoothing 4. prediction and smoothing | |||
| Type | Answer | Responses | Percent |
| Correct: | smoothing | 50 | 88% |
| Distractor: | tracking (or filtering) | 0 | 0% |
| Distractor: | prediction | 0 | 0% |
| Distractor: | prediction and smoothing | 7 | 12% |
Question 5: In which of the following 2-TBNs will (X(t) ⊥ Z(t) | Y(t)) hold over time, assuming Obs(t) is observed for all t and the others are never observed? Answers: 1. (a) 2. (b) 3. (c) 4. All of the above | |||
| Type | Answer | Responses | Percent |
| Correct: | (b) | 29 | 51% |
| Distractor: | (a) | 2 | 4% |
| Distractor: | (c) | 1 | 2% |
| Distractor: | All of the above | 25 | 44% |
| Question 6: Given the 2-TBN shown below, if we have belief state [0.5, 0.5] at time t, what is the belief state at time t+1?
| |||
| Type | Answer | Responses | Percent |
| Correct: | [0.5, 0.5] | 57 | 100% |
| Distractor: | [0.2, 0.8] | 0 | 0% |
| Distractor: | [0.8, 0.2] | 0 | 0% |
| Distractor: | [0.0, 1.0] | 0 | 0% |
| Question 7: Consider the 2-TBN shown below, with O always observed. If we observe O(t) = 0 at some time t in the unrolled DBN, then which of the following represents the belief state X(t)?
| |||
| Type | Answer | Responses | Percent |
| Correct: | can't be determined | 40 | 70% |
| Distractor: | [1.0, 0.0] | 2 | 4% |
| Distractor: | [0.2, 0.8] | 0 | 0% |
| Distractor: | [0.67, 0.33] | 15 | 26% |